5(x^2+4)=29x

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Solution for 5(x^2+4)=29x equation:


Simplifying
5(x2 + 4) = 29x

Reorder the terms:
5(4 + x2) = 29x
(4 * 5 + x2 * 5) = 29x
(20 + 5x2) = 29x

Solving
20 + 5x2 = 29x

Solving for variable 'x'.

Reorder the terms:
20 + -29x + 5x2 = 29x + -29x

Combine like terms: 29x + -29x = 0
20 + -29x + 5x2 = 0

Factor a trinomial.
(4 + -5x)(5 + -1x) = 0

Subproblem 1

Set the factor '(4 + -5x)' equal to zero and attempt to solve: Simplifying 4 + -5x = 0 Solving 4 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5x = 0 + -4 -5x = 0 + -4 Combine like terms: 0 + -4 = -4 -5x = -4 Divide each side by '-5'. x = 0.8 Simplifying x = 0.8

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {0.8, 5}

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